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53796016431361 = 918725309231367
BaseRepresentation
bin11000011101101010111000…
…11100110010000100000001
321001110211220212210000201101
430032311130130302010001
524022343220201300421
6310225314311334401
714221430302620421
oct1416653434620401
9231424825700641
1053796016431361
11161608428a8476
12604a041081401
132402c33b11b29
14d3da5378c481
15634557ab9191
hex30ed5c732101

53796016431361 has 8 divisors (see below), whose sum is σ = 53804230447040. Its totient is φ = 53787802947408.

The previous prime is 53796016431347. The next prime is 53796016431373. The reversal of 53796016431361 is 16313461069735.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53796016431361 is a prime.

It is a super-2 number, since 2×537960164313612 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53796016431331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 232398100 + ... + 232629466.

It is an arithmetic number, because the mean of its divisors is an integer number (6725528805880).

Almost surely, 253796016431361 is an apocalyptic number.

It is an amenable number.

53796016431361 is a deficient number, since it is larger than the sum of its proper divisors (8214015679).

53796016431361 is a wasteful number, since it uses less digits than its factorization.

53796016431361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265863.

The product of its (nonzero) digits is 7348320, while the sum is 55.

The spelling of 53796016431361 in words is "fifty-three trillion, seven hundred ninety-six billion, sixteen million, four hundred thirty-one thousand, three hundred sixty-one".

Divisors: 1 9187 25309 231367 232513783 2125568629 5855667403 53796016431361