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53796016431373 is a prime number
BaseRepresentation
bin11000011101101010111000…
…11100110010000100001101
321001110211220212210000201211
430032311130130302010031
524022343220201300443
6310225314311334421
714221430302620436
oct1416653434620415
9231424825700654
1053796016431373
11161608428a8487
12604a041081411
132402c33b11b38
14d3da5378c48d
15634557ab919d
hex30ed5c73210d

53796016431373 has 2 divisors, whose sum is σ = 53796016431374. Its totient is φ = 53796016431372.

The previous prime is 53796016431347. The next prime is 53796016431407. The reversal of 53796016431373 is 37313461069735.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53605782630409 + 190233800964 = 7321597^2 + 436158^2 .

It is a cyclic number.

It is not a de Polignac number, because 53796016431373 - 245 = 18611644342541 is a prime.

It is a super-2 number, since 2×537960164313732 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53796016434373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26898008215686 + 26898008215687.

It is an arithmetic number, because the mean of its divisors is an integer number (26898008215687).

Almost surely, 253796016431373 is an apocalyptic number.

It is an amenable number.

53796016431373 is a deficient number, since it is larger than the sum of its proper divisors (1).

53796016431373 is an equidigital number, since it uses as much as digits as its factorization.

53796016431373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25719120, while the sum is 58.

The spelling of 53796016431373 in words is "fifty-three trillion, seven hundred ninety-six billion, sixteen million, four hundred thirty-one thousand, three hundred seventy-three".