Base | Representation |
---|---|
bin | 11000011101101010111000… |
… | …11100110010000100001101 |
3 | 21001110211220212210000201211 |
4 | 30032311130130302010031 |
5 | 24022343220201300443 |
6 | 310225314311334421 |
7 | 14221430302620436 |
oct | 1416653434620415 |
9 | 231424825700654 |
10 | 53796016431373 |
11 | 161608428a8487 |
12 | 604a041081411 |
13 | 2402c33b11b38 |
14 | d3da5378c48d |
15 | 634557ab919d |
hex | 30ed5c73210d |
53796016431373 has 2 divisors, whose sum is σ = 53796016431374. Its totient is φ = 53796016431372.
The previous prime is 53796016431347. The next prime is 53796016431407. The reversal of 53796016431373 is 37313461069735.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53605782630409 + 190233800964 = 7321597^2 + 436158^2 .
It is a cyclic number.
It is not a de Polignac number, because 53796016431373 - 245 = 18611644342541 is a prime.
It is a super-2 number, since 2×537960164313732 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53796016434373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26898008215686 + 26898008215687.
It is an arithmetic number, because the mean of its divisors is an integer number (26898008215687).
Almost surely, 253796016431373 is an apocalyptic number.
It is an amenable number.
53796016431373 is a deficient number, since it is larger than the sum of its proper divisors (1).
53796016431373 is an equidigital number, since it uses as much as digits as its factorization.
53796016431373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25719120, while the sum is 58.
The spelling of 53796016431373 in words is "fifty-three trillion, seven hundred ninety-six billion, sixteen million, four hundred thirty-one thousand, three hundred seventy-three".
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