Base | Representation |
---|---|
bin | 111101001011001111011100… |
… | …0100110101110100000011111 |
3 | 2121120021111100200020201201122 |
4 | 1322112132320212232200133 |
5 | 1031012314422140224123 |
6 | 5144242442241201155 |
7 | 221225631534235016 |
oct | 17226367046564037 |
9 | 2546244320221648 |
10 | 538106664773663 |
11 | 146503833942267 |
12 | 504288153301bb |
13 | 1a134318c29b7b |
14 | 96c470431da7d |
15 | 42325c8a24bc8 |
hex | 1e967b89ae81f |
538106664773663 has 12 divisors (see below), whose sum is σ = 562523066565600. Its totient is φ = 514707753643776.
The previous prime is 538106664773611. The next prime is 538106664773669. The reversal of 538106664773663 is 366377466601835.
It is not a de Polignac number, because 538106664773663 - 26 = 538106664773599 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (538106664773669) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 91740095 + ... + 97429247.
It is an arithmetic number, because the mean of its divisors is an integer number (46876922213800).
Almost surely, 2538106664773663 is an apocalyptic number.
538106664773663 is a deficient number, since it is larger than the sum of its proper divisors (24416401791937).
538106664773663 is a wasteful number, since it uses less digits than its factorization.
538106664773663 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5867998 (or 5867975 counting only the distinct ones).
The product of its (nonzero) digits is 1646023680, while the sum is 71.
The spelling of 538106664773663 in words is "five hundred thirty-eight trillion, one hundred six billion, six hundred sixty-four million, seven hundred seventy-three thousand, six hundred sixty-three".
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