Base | Representation |
---|---|
bin | 1010000001110010… |
… | …01110111010110001 |
3 | 111220012101221001210 |
4 | 11000321032322301 |
5 | 42011212244213 |
6 | 2250115350333 |
7 | 250261541421 |
oct | 50071167261 |
9 | 14805357053 |
10 | 5383712433 |
11 | 2312a68920 |
12 | 1062bb23a9 |
13 | 67a4b9778 |
14 | 391026481 |
15 | 21799e0c3 |
hex | 140e4eeb1 |
5383712433 has 32 divisors (see below), whose sum is σ = 8132124672. Its totient is φ = 3138595200.
The previous prime is 5383712429. The next prime is 5383712471. The reversal of 5383712433 is 3342173835.
It is not a de Polignac number, because 5383712433 - 22 = 5383712429 is a prime.
It is a super-2 number, since 2×53837124332 = 57968719122477558978, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5383712391 and 5383712400.
It is not an unprimeable number, because it can be changed into a prime (5383712423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 155085 + ... + 186597.
It is an arithmetic number, because the mean of its divisors is an integer number (254128896).
Almost surely, 25383712433 is an apocalyptic number.
It is an amenable number.
5383712433 is a deficient number, since it is larger than the sum of its proper divisors (2748412239).
5383712433 is a wasteful number, since it uses less digits than its factorization.
5383712433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31725.
The product of its digits is 181440, while the sum is 39.
The square root of 5383712433 is about 73373.7857344161. The cubic root of 5383712433 is about 1752.6449726394.
The spelling of 5383712433 in words is "five billion, three hundred eighty-three million, seven hundred twelve thousand, four hundred thirty-three".
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