Base | Representation |
---|---|
bin | 111101001111110101101110… |
… | …1101100010000000101001011 |
3 | 2121122111220121121121221001111 |
4 | 1322133223131230100011023 |
5 | 1031103143222133441103 |
6 | 5145445041241231151 |
7 | 221322403621052110 |
oct | 17237533554200513 |
9 | 2548456547557044 |
10 | 538738647171403 |
11 | 146727860493628 |
12 | 5050b1aaa924b7 |
13 | 1a17bab4872883 |
14 | 9707138004907 |
15 | 4243c6655386d |
hex | 1e9faddb1014b |
538738647171403 has 8 divisors (see below), whose sum is σ = 615702385099008. Its totient is φ = 461775177755304.
The previous prime is 538738647171341. The next prime is 538738647171433. The reversal of 538738647171403 is 304171746837835.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 538738647171403 - 29 = 538738647170891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (538738647171433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62809951 + ... + 70870072.
It is an arithmetic number, because the mean of its divisors is an integer number (76962798137376).
Almost surely, 2538738647171403 is an apocalyptic number.
538738647171403 is a deficient number, since it is larger than the sum of its proper divisors (76963737927605).
538738647171403 is a wasteful number, since it uses less digits than its factorization.
538738647171403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 134255753.
The product of its (nonzero) digits is 284497920, while the sum is 67.
The spelling of 538738647171403 in words is "five hundred thirty-eight trillion, seven hundred thirty-eight billion, six hundred forty-seven million, one hundred seventy-one thousand, four hundred three".
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