Base | Representation |
---|---|
bin | 11000100001110011001100… |
… | …01010001000101111111111 |
3 | 21001222102011220122120220222 |
4 | 30100321212022020233333 |
5 | 24032204321242031404 |
6 | 310414422452331555 |
7 | 14234612525561666 |
oct | 1420714612105777 |
9 | 231872156576828 |
10 | 53937913236479 |
11 | 16205a38955348 |
12 | 6071642013bbb |
13 | 24134286593cc |
14 | d46874c91ddd |
15 | 6380b00b6dbe |
hex | 310e66288bff |
53937913236479 has 4 divisors (see below), whose sum is σ = 53937930469584. Its totient is φ = 53937896003376.
The previous prime is 53937913236439. The next prime is 53937913236491. The reversal of 53937913236479 is 97463231973935.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53937913236479 - 232 = 53933618269183 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53937913236439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2451227 + ... + 10671660.
It is an arithmetic number, because the mean of its divisors is an integer number (13484482617396).
Almost surely, 253937913236479 is an apocalyptic number.
53937913236479 is a deficient number, since it is larger than the sum of its proper divisors (17233105).
53937913236479 is a wasteful number, since it uses less digits than its factorization.
53937913236479 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17233104.
The product of its digits is 694416240, while the sum is 71.
The spelling of 53937913236479 in words is "fifty-three trillion, nine hundred thirty-seven billion, nine hundred thirteen million, two hundred thirty-six thousand, four hundred seventy-nine".
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