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5399048170645 = 51079809634129
BaseRepresentation
bin100111010010001000001…
…0110010010110010010101
3201010010212221122112222221
41032210100112102302111
51201424222312430040
615252142151422341
71065032306150353
oct116442026226225
921103787575887
105399048170645
1117a17a5a37428
127324563849b1
1330218845cc6c
1414945b37a7d3
15956957a174a
hex4e910592c95

5399048170645 has 4 divisors (see below), whose sum is σ = 6478857804780. Its totient is φ = 4319238536512.

The previous prime is 5399048170601. The next prime is 5399048170667. The reversal of 5399048170645 is 5460718409935.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2585541793444 + 2813506377201 = 1607962^2 + 1677351^2 .

It is a cyclic number.

It is not a de Polignac number, because 5399048170645 - 215 = 5399048137877 is a prime.

It is a super-2 number, since 2×53990481706452 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 539904817060 + ... + 539904817069.

It is an arithmetic number, because the mean of its divisors is an integer number (1619714451195).

Almost surely, 25399048170645 is an apocalyptic number.

It is an amenable number.

5399048170645 is a deficient number, since it is larger than the sum of its proper divisors (1079809634135).

5399048170645 is a wasteful number, since it uses less digits than its factorization.

5399048170645 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1079809634134.

The product of its (nonzero) digits is 32659200, while the sum is 61.

The spelling of 5399048170645 in words is "five trillion, three hundred ninety-nine billion, forty-eight million, one hundred seventy thousand, six hundred forty-five".

Divisors: 1 5 1079809634129 5399048170645