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53993112453 = 327857033531
BaseRepresentation
bin110010010010001111…
…011000001110000101
312011100212120022010200
4302102033120032011
51341034214044303
640445403441113
73620666612010
oct622217301605
9164325508120
1053993112453
1120997782595
12a56a226199
13512611c467
142882bb0377
1516102093a3
hexc923d8385

53993112453 has 12 divisors (see below), whose sum is σ = 89131487328. Its totient is φ = 30853207080.

The previous prime is 53993112449. The next prime is 53993112473. The reversal of 53993112453 is 35421139935.

53993112453 is a `hidden beast` number, since 5 + 3 + 99 + 311 + 245 + 3 = 666.

It is not a de Polignac number, because 53993112453 - 22 = 53993112449 is a prime.

It is a hoax number, since the sum of its digits (45) coincides with the sum of the digits of its distinct prime factors.

It is a junction number, because it is equal to n+sod(n) for n = 53993112399 and 53993112408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53993112413) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 428516703 + ... + 428516828.

It is an arithmetic number, because the mean of its divisors is an integer number (7427623944).

Almost surely, 253993112453 is an apocalyptic number.

It is an amenable number.

53993112453 is a deficient number, since it is larger than the sum of its proper divisors (35138374875).

53993112453 is a wasteful number, since it uses less digits than its factorization.

53993112453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 857033544 (or 857033541 counting only the distinct ones).

The product of its digits is 437400, while the sum is 45.

The spelling of 53993112453 in words is "fifty-three billion, nine hundred ninety-three million, one hundred twelve thousand, four hundred fifty-three".

Divisors: 1 3 7 9 21 63 857033531 2571100593 5999234717 7713301779 17997704151 53993112453