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5400144403 = 15713437393
BaseRepresentation
bin1010000011101111…
…11010101000010011
3111221100022202111021
411001313322220103
542024414110103
62251503500311
7250551320143
oct50167725023
914840282437
105400144403
112321271465
1210685b7697
13680a20b24
143932a2923
15219147bbd
hex141dfaa13

5400144403 has 4 divisors (see below), whose sum is σ = 5403583368. Its totient is φ = 5396705440.

The previous prime is 5400144391. The next prime is 5400144467. The reversal of 5400144403 is 3044410045.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5400144403 - 25 = 5400144371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5400244403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1717126 + ... + 1720267.

It is an arithmetic number, because the mean of its divisors is an integer number (1350895842).

Almost surely, 25400144403 is an apocalyptic number.

5400144403 is a deficient number, since it is larger than the sum of its proper divisors (3438965).

5400144403 is a wasteful number, since it uses less digits than its factorization.

5400144403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3438964.

The product of its (nonzero) digits is 3840, while the sum is 25.

The square root of 5400144403 is about 73485.6748148916. The cubic root of 5400144403 is about 1754.4262811933.

Adding to 5400144403 its reverse (3044410045), we get a palindrome (8444554448).

The spelling of 5400144403 in words is "five billion, four hundred million, one hundred forty-four thousand, four hundred three".

Divisors: 1 1571 3437393 5400144403