540024521120433 has 12 divisors (see below), whose sum is σ = 782350064561988. Its totient is φ = 358948049644800.

The previous prime is 540024521120411. The next prime is 540024521120501. The reversal of 540024521120433 is 334021125420045.

It is a happy number.

540024521120433 is a `hidden beast` number, since 5 + 4 + 0 + 0 + 2 + 4 + 5 + 211 + 2 + 0 + 433 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 266416432663824 + 273608088456609 = 16322268^2 + 16541103^2 .

It is not a de Polignac number, because 540024521120433 - 2⁸ = 540024521120177 is a prime.

It is a super-2 number, since 2×540024521120433² (a number of 30 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (540024521120233) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 89024810868 + ... + 89024816933.

It is an arithmetic number, because the mean of its divisors is an integer number (65195838713499).

Almost surely, 2^{540024521120433} is an apocalyptic number.

It is an amenable number.

540024521120433 is a deficient number, since it is larger than the sum of its proper divisors (242325543441555).

540024521120433 is a wasteful number, since it uses less digits than its factorization.

540024521120433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178049628144 (or 178049628141 counting only the distinct ones).

The product of its (nonzero) digits is 115200, while the sum is 36.

Adding to 540024521120433 its reverse (334021125420045), we get a palindrome (874045646540478).

The spelling of 540024521120433 in words is "five hundred forty trillion, twenty-four billion, five hundred twenty-one million, one hundred twenty thousand, four hundred thirty-three".