Base | Representation |
---|---|
bin | 111101011001010001100110… |
… | …0101000111011101011000101 |
3 | 2121211002212212102101202220020 |
4 | 1322302203030220323223011 |
5 | 1031240420040422241401 |
6 | 5152320505022125353 |
7 | 221515162444403412 |
oct | 17262431450735305 |
9 | 2554085772352806 |
10 | 540035441212101 |
11 | 14708782096207a |
12 | 5069a5a0720859 |
13 | 1a24417b6c2b73 |
14 | 974dbd7893109 |
15 | 4267863c9ed36 |
hex | 1eb28cca3bac5 |
540035441212101 has 16 divisors (see below), whose sum is σ = 723465897842688. Its totient is φ = 358314334786800.
The previous prime is 540035441212093. The next prime is 540035441212123. The reversal of 540035441212101 is 101212144530045.
It is not a de Polignac number, because 540035441212101 - 23 = 540035441212093 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (540035441212171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72863020 + ... + 79931786.
It is an arithmetic number, because the mean of its divisors is an integer number (45216618615168).
Almost surely, 2540035441212101 is an apocalyptic number.
It is an amenable number.
540035441212101 is a deficient number, since it is larger than the sum of its proper divisors (183430456630587).
540035441212101 is a wasteful number, since it uses less digits than its factorization.
540035441212101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7189672.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 540035441212101 its reverse (101212144530045), we get a palindrome (641247585742146).
The spelling of 540035441212101 in words is "five hundred forty trillion, thirty-five billion, four hundred forty-one million, two hundred twelve thousand, one hundred one".
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