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5400411303 = 37647397469
BaseRepresentation
bin1010000011110001…
…11011110010100111
3111221100211022121110
411001320323302213
542030001130203
62251513320103
7250553511240
oct50170736247
914840738543
105400411303
112321433a41
121068706033
13680ab5461
14393331cc7
1521919bd03
hex141e3bca7

5400411303 has 16 divisors (see below), whose sum is σ = 8241937920. Its totient is φ = 3081171936.

The previous prime is 5400411299. The next prime is 5400411311. The reversal of 5400411303 is 3031140045.

It is not a de Polignac number, because 5400411303 - 22 = 5400411299 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a self number, because there is not a number n which added to its sum of digits gives 5400411303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5400411353) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 185148 + ... + 212321.

It is an arithmetic number, because the mean of its divisors is an integer number (515121120).

Almost surely, 25400411303 is an apocalyptic number.

5400411303 is a deficient number, since it is larger than the sum of its proper divisors (2841526617).

5400411303 is a wasteful number, since it uses less digits than its factorization.

5400411303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 398126.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 5400411303 is about 73487.4907926512. The cubic root of 5400411303 is about 1754.4551846586.

Adding to 5400411303 its reverse (3031140045), we get a palindrome (8431551348).

The spelling of 5400411303 in words is "five billion, four hundred million, four hundred eleven thousand, three hundred three".

Divisors: 1 3 7 21 647 1941 4529 13587 397469 1192407 2782283 8346849 257162443 771487329 1800137101 5400411303