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540042215403 = 31619571111493
BaseRepresentation
bin1111101101111010000…
…01100011111111101011
31220121221110201000101110
413312331001203333223
532322001301343103
61052031510521403
754005515043205
oct7667501437753
91817843630343
10540042215403
1119903782a5a9
12887b7066263
133bc05b91362
141c1d125d775
15e0ab1a8403
hex7dbd063feb

540042215403 has 8 divisors (see below), whose sum is σ = 720061381008. Its totient is φ = 360025596704.

The previous prime is 540042215393. The next prime is 540042215459. The reversal of 540042215403 is 304512240045.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 540042215403 - 25 = 540042215371 is a prime.

It is a super-3 number, since 3×5400422154033 (a number of 36 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (540042215203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69876 + ... + 1041617.

It is an arithmetic number, because the mean of its divisors is an integer number (90007672626).

Almost surely, 2540042215403 is an apocalyptic number.

540042215403 is a deficient number, since it is larger than the sum of its proper divisors (180019165605).

540042215403 is a wasteful number, since it uses less digits than its factorization.

540042215403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1273453.

The product of its (nonzero) digits is 19200, while the sum is 30.

Adding to 540042215403 its reverse (304512240045), we get a palindrome (844554455448).

The spelling of 540042215403 in words is "five hundred forty billion, forty-two million, two hundred fifteen thousand, four hundred three".

Divisors: 1 3 161957 485871 1111493 3334479 180014071801 540042215403