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54010446433 = 235092297437
BaseRepresentation
bin110010010011010001…
…100000001001100001
312011102002011221212221
4302103101200021201
51341103133241213
640451223151041
73621300135256
oct622321401141
9164362157787
1054010446433
11209a6541899
12a573ba5481
1351298ab258
14288520342d
1516119d038d
hexc93460261

54010446433 has 4 divisors (see below), whose sum is σ = 54012767380. Its totient is φ = 54008125488.

The previous prime is 54010446421. The next prime is 54010446439. The reversal of 54010446433 is 33464401045.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 46006818064 + 8003628369 = 214492^2 + 89463^2 .

It is a cyclic number.

It is not a de Polignac number, because 54010446433 - 233 = 45420511841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54010446439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125210 + ... + 1172227.

It is an arithmetic number, because the mean of its divisors is an integer number (13503191845).

Almost surely, 254010446433 is an apocalyptic number.

It is an amenable number.

54010446433 is a deficient number, since it is larger than the sum of its proper divisors (2320947).

54010446433 is a wasteful number, since it uses less digits than its factorization.

54010446433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2320946.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 54010446433 its reverse (33464401045), we get a palindrome (87474847478).

The spelling of 54010446433 in words is "fifty-four billion, ten million, four hundred forty-six thousand, four hundred thirty-three".

Divisors: 1 23509 2297437 54010446433