Base | Representation |
---|---|
bin | 111101011001110110001100… |
… | …0011111000011001110100001 |
3 | 2121211101101200221002100122121 |
4 | 1322303230120133003032201 |
5 | 1031243212004403220340 |
6 | 5152420542400504241 |
7 | 221523643666422340 |
oct | 17263543037031641 |
9 | 2554341627070577 |
10 | 540114023101345 |
11 | 14710808632a5a0 |
12 | 506b187161b081 |
13 | 1a24b6c2aa7994 |
14 | 9753930163b57 |
15 | 42699129ec94a |
hex | 1eb3b187c33a1 |
540114023101345 has 128 divisors (see below), whose sum is σ = 840276770623488. Its totient is φ = 323550194688000.
The previous prime is 540114023101249. The next prime is 540114023101409. The reversal of 540114023101345 is 543101320411045.
It is not a de Polignac number, because 540114023101345 - 217 = 540114022970273 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 540114023101345.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 484057254 + ... + 485171776.
It is an arithmetic number, because the mean of its divisors is an integer number (6564662270496).
Almost surely, 2540114023101345 is an apocalyptic number.
540114023101345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
540114023101345 is a deficient number, since it is larger than the sum of its proper divisors (300162747522143).
540114023101345 is a wasteful number, since it uses less digits than its factorization.
540114023101345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1115063.
The product of its (nonzero) digits is 28800, while the sum is 34.
The spelling of 540114023101345 in words is "five hundred forty trillion, one hundred fourteen billion, twenty-three million, one hundred one thousand, three hundred forty-five".
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