Base | Representation |
---|---|
bin | 110010010011011001… |
… | …000100101110000001 |
3 | 12011102012220210112001 |
4 | 302103121010232001 |
5 | 1341104140244413 |
6 | 40451333504001 |
7 | 3621323042665 |
oct | 622331045601 |
9 | 164365823461 |
10 | 54012431233 |
11 | 209a7678022 |
12 | a5747a2001 |
13 | 512a1247a7 |
14 | 288559c8a5 |
15 | 1611c734dd |
hex | c93644b81 |
54012431233 has 4 divisors (see below), whose sum is σ = 54026417088. Its totient is φ = 53998445380.
The previous prime is 54012431227. The next prime is 54012431257. The reversal of 54012431233 is 33213421045.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 54012431233 - 25 = 54012431201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54012435233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6987133 + ... + 6994858.
It is an arithmetic number, because the mean of its divisors is an integer number (13506604272).
Almost surely, 254012431233 is an apocalyptic number.
It is an amenable number.
54012431233 is a deficient number, since it is larger than the sum of its proper divisors (13985855).
54012431233 is a wasteful number, since it uses less digits than its factorization.
54012431233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13985854.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 54012431233 its reverse (33213421045), we get a palindrome (87225852278).
The spelling of 54012431233 in words is "fifty-four billion, twelve million, four hundred thirty-one thousand, two hundred thirty-three".
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