Base | Representation |
---|---|
bin | 110010010011011001… |
… | …000111001100111011 |
3 | 12011102012221022110201 |
4 | 302103121013030323 |
5 | 1341104141111103 |
6 | 40451334023031 |
7 | 3621323114434 |
oct | 622331071473 |
9 | 164365838421 |
10 | 54012441403 |
11 | 209a7684728 |
12 | a5747a7a77 |
13 | 512a1292cb |
14 | 28855a248b |
15 | 1611c7651d |
hex | c9364733b |
54012441403 has 8 divisors (see below), whose sum is σ = 54430111296. Its totient is φ = 53594853000.
The previous prime is 54012441377. The next prime is 54012441419. The reversal of 54012441403 is 30414421045.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54012441403 - 225 = 53978886971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54012481403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2616400 + ... + 2636962.
It is an arithmetic number, because the mean of its divisors is an integer number (6803763912).
Almost surely, 254012441403 is an apocalyptic number.
54012441403 is a deficient number, since it is larger than the sum of its proper divisors (417669893).
54012441403 is a wasteful number, since it uses less digits than its factorization.
54012441403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40745.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 54012441403 its reverse (30414421045), we get a palindrome (84426862448).
The spelling of 54012441403 in words is "fifty-four billion, twelve million, four hundred forty-one thousand, four hundred three".
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