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54012441403 = 1312005120563
BaseRepresentation
bin110010010011011001…
…000111001100111011
312011102012221022110201
4302103121013030323
51341104141111103
640451334023031
73621323114434
oct622331071473
9164365838421
1054012441403
11209a7684728
12a5747a7a77
13512a1292cb
1428855a248b
151611c7651d
hexc9364733b

54012441403 has 8 divisors (see below), whose sum is σ = 54430111296. Its totient is φ = 53594853000.

The previous prime is 54012441377. The next prime is 54012441419. The reversal of 54012441403 is 30414421045.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 54012441403 - 225 = 53978886971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54012481403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2616400 + ... + 2636962.

It is an arithmetic number, because the mean of its divisors is an integer number (6803763912).

Almost surely, 254012441403 is an apocalyptic number.

54012441403 is a deficient number, since it is larger than the sum of its proper divisors (417669893).

54012441403 is a wasteful number, since it uses less digits than its factorization.

54012441403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40745.

The product of its (nonzero) digits is 7680, while the sum is 28.

Adding to 54012441403 its reverse (30414421045), we get a palindrome (84426862448).

The spelling of 54012441403 in words is "fifty-four billion, twelve million, four hundred forty-one thousand, four hundred three".

Divisors: 1 131 20051 20563 2626681 2693753 412308713 54012441403