Base | Representation |
---|---|
bin | 111101011010000100100111… |
… | …1101100011001111000111011 |
3 | 2121211111100200202011020001011 |
4 | 1322310021033230121320323 |
5 | 1031244213442103314440 |
6 | 5152443105513534351 |
7 | 221526121661634364 |
oct | 17264111754317073 |
9 | 2554440622136034 |
10 | 540145014119995 |
11 | 14711a239a125a9 |
12 | 506b78804143b7 |
13 | 1a2515c1583c3b |
14 | 975523005cb6b |
15 | 426a6286319ea |
hex | 1eb424fb19e3b |
540145014119995 has 32 divisors (see below), whose sum is σ = 666140263963200. Its totient is φ = 420154258761216.
The previous prime is 540145014119987. The next prime is 540145014119999. The reversal of 540145014119995 is 599911410541045.
It is a cyclic number.
It is not a de Polignac number, because 540145014119995 - 23 = 540145014119987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (540145014119999) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12059747061 + ... + 12059791849.
It is an arithmetic number, because the mean of its divisors is an integer number (20816883248850).
Almost surely, 2540145014119995 is an apocalyptic number.
540145014119995 is a deficient number, since it is larger than the sum of its proper divisors (125995249843205).
540145014119995 is a wasteful number, since it uses less digits than its factorization.
540145014119995 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87247.
The product of its (nonzero) digits is 5832000, while the sum is 58.
The spelling of 540145014119995 in words is "five hundred forty trillion, one hundred forty-five billion, fourteen million, one hundred nineteen thousand, nine hundred ninety-five".
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