Base | Representation |
---|---|
bin | 110010010011100111… |
… | …001000011000001011 |
3 | 12011102110212000101121 |
4 | 302103213020120023 |
5 | 1341111111204420 |
6 | 40451544500111 |
7 | 3621366261304 |
oct | 622347103013 |
9 | 164373760347 |
10 | 54016116235 |
11 | 209a9764684 |
12 | a575a7a637 |
13 | 512ab14b73 |
14 | 2885c7b7ab |
15 | 16122502aa |
hex | c939c860b |
54016116235 has 4 divisors (see below), whose sum is σ = 64819339488. Its totient is φ = 43212892984.
The previous prime is 54016116233. The next prime is 54016116263. The reversal of 54016116235 is 53261161045.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54016116235 - 21 = 54016116233 is a prime.
It is a super-3 number, since 3×540161162353 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 54016116235.
It is not an unprimeable number, because it can be changed into a prime (54016116233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5401611619 + ... + 5401611628.
It is an arithmetic number, because the mean of its divisors is an integer number (16204834872).
Almost surely, 254016116235 is an apocalyptic number.
54016116235 is a deficient number, since it is larger than the sum of its proper divisors (10803223253).
54016116235 is a wasteful number, since it uses less digits than its factorization.
54016116235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10803223252.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 54016116235 in words is "fifty-four billion, sixteen million, one hundred sixteen thousand, two hundred thirty-five".
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