Search a number
-
+
5402001435311 = 13415538571947
BaseRepresentation
bin100111010011100000001…
…1000000110101010101111
3201010102111202201221111202
41032213000120012222233
51202001244331412221
615253351210240115
71065165426403415
oct116470030065257
921112452657452
105402001435311
1117a2a80a86928
12732b3b42603b
13302539260050
1414965b6992b5
15957b9bb2d0b
hex4e9c0606aaf

5402001435311 has 4 divisors (see below), whose sum is σ = 5817540007272. Its totient is φ = 4986462863352.

The previous prime is 5402001435293. The next prime is 5402001435343. The reversal of 5402001435311 is 1135341002045.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5402001435311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5402001435811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207769285961 + ... + 207769285986.

It is an arithmetic number, because the mean of its divisors is an integer number (1454385001818).

Almost surely, 25402001435311 is an apocalyptic number.

5402001435311 is a deficient number, since it is larger than the sum of its proper divisors (415538571961).

5402001435311 is a wasteful number, since it uses less digits than its factorization.

5402001435311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 415538571960.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 5402001435311 its reverse (1135341002045), we get a palindrome (6537342437356).

The spelling of 5402001435311 in words is "five trillion, four hundred two billion, one million, four hundred thirty-five thousand, three hundred eleven".

Divisors: 1 13 415538571947 5402001435311