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5402001439999 = 43312475753903
BaseRepresentation
bin100111010011100000001…
…1000000111110011111111
3201010102111202202011221101
41032213000120013303333
51202001244332034444
615253351210313531
71065165426423163
oct116470030076377
921112452664841
105402001439999
1117a2a80a8a3aa
12732b3b4288a7
13302539262218
1414965b69aca3
15957b9bb43d4
hex4e9c0607cff

5402001439999 has 4 divisors (see below), whose sum is σ = 5414477194336. Its totient is φ = 5389525685664.

The previous prime is 5402001439873. The next prime is 5402001440009. The reversal of 5402001439999 is 9999341002045.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5402001439999 - 231 = 5399853956351 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5402001433999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6237876519 + ... + 6237877384.

It is an arithmetic number, because the mean of its divisors is an integer number (1353619298584).

Almost surely, 25402001439999 is an apocalyptic number.

5402001439999 is a deficient number, since it is larger than the sum of its proper divisors (12475754337).

5402001439999 is a wasteful number, since it uses less digits than its factorization.

5402001439999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12475754336.

The product of its (nonzero) digits is 3149280, while the sum is 55.

The spelling of 5402001439999 in words is "five trillion, four hundred two billion, one million, four hundred thirty-nine thousand, nine hundred ninety-nine".

Divisors: 1 433 12475753903 5402001439999