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5402201803 = 6693180713
BaseRepresentation
bin1010000011111111…
…10000111011001011
3111221111012021201021
411001333300323023
542030430424203
62252015533311
7250604646325
oct50177607313
914844167637
105402201803
112322447199
12106922a237
1368129141b
1439367a615
152194025bd
hex141ff0ecb

5402201803 has 4 divisors (see below), whose sum is σ = 5402349448. Its totient is φ = 5402054160.

The previous prime is 5402201743. The next prime is 5402201807. The reversal of 5402201803 is 3081022045.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5402201803 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5402201807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26575 + ... + 107287.

It is an arithmetic number, because the mean of its divisors is an integer number (1350587362).

Almost surely, 25402201803 is an apocalyptic number.

5402201803 is a deficient number, since it is larger than the sum of its proper divisors (147645).

5402201803 is an equidigital number, since it uses as much as digits as its factorization.

5402201803 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147644.

The product of its (nonzero) digits is 1920, while the sum is 25.

The square root of 5402201803 is about 73499.6721285204. The cubic root of 5402201803 is about 1754.6490590832.

Adding to 5402201803 its reverse (3081022045), we get a palindrome (8483223848).

The spelling of 5402201803 in words is "five billion, four hundred two million, two hundred one thousand, eight hundred three".

Divisors: 1 66931 80713 5402201803