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54031203313 = 593929233083
BaseRepresentation
bin110010010100100000…
…101011101111110001
312011110112020111222021
4302110200223233301
51341123442001223
640453244111441
73621641436043
oct622440535761
9164415214867
1054031203313
1120a0722983a
12a57ab35581
135130c98029
142887c87a93
15161373065d
hexc9482bbf1

54031203313 has 8 divisors (see below), whose sum is σ = 54961207200. Its totient is φ = 53101673568.

The previous prime is 54031203301. The next prime is 54031203349. The reversal of 54031203313 is 31330213045.

54031203313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 54031203313 - 217 = 54031072241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54031203613) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 115270 + ... + 348352.

It is an arithmetic number, because the mean of its divisors is an integer number (6870150900).

Almost surely, 254031203313 is an apocalyptic number.

It is an amenable number.

54031203313 is a deficient number, since it is larger than the sum of its proper divisors (930003887).

54031203313 is a wasteful number, since it uses less digits than its factorization.

54031203313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237071.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 54031203313 its reverse (31330213045), we get a palindrome (85361416358).

The spelling of 54031203313 in words is "fifty-four billion, thirty-one million, two hundred three thousand, three hundred thirteen".

Divisors: 1 59 3929 231811 233083 13751897 915783107 54031203313