540313132531 has 4 divisors (see below), whose sum is σ = 572096257992. Its totient is φ = 508530007072.

The previous prime is 540313132459. The next prime is 540313132603. The reversal of 540313132531 is 135231313045.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (540313132459) and next prime (540313132603).

It is a cyclic number.

It is not a de Polignac number, because 540313132531 - 2¹⁵ = 540313099763 is a prime.

It is a super-2 number, since 2×540313132531² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 540313132493 and 540313132502.

It is not an unprimeable number, because it can be changed into a prime (540313132631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15891562705 + ... + 15891562738.

It is an arithmetic number, because the mean of its divisors is an integer number (143024064498).

Almost surely, 2^540313132531 is an apocalyptic number.

540313132531 is a deficient number, since it is larger than the sum of its proper divisors (31783125461).

540313132531 is a wasteful number, since it uses less digits than its factorization.

540313132531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31783125460.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 540313132531 its reverse (135231313045), we get a palindrome (675544445576).

The spelling of 540313132531 in words is "five hundred forty billion, three hundred thirteen million, one hundred thirty-two thousand, five hundred thirty-one".