Base | Representation |
---|---|
bin | 100111010100011101000… |
… | …1001011100110000110011 |
3 | 201010121210010222000102020 |
4 | 1032220322021130300303 |
5 | 1202014440332222003 |
6 | 15254330030322523 |
7 | 1065300154420464 |
oct | 116507211346063 |
9 | 21117703860366 |
10 | 5404044414003 |
11 | 17a392a208a74 |
12 | 73340b659443 |
13 | 3027a35a4991 |
14 | 1497b2b40d6b |
15 | 95889214d53 |
hex | 4ea3a25cc33 |
5404044414003 has 16 divisors (see below), whose sum is σ = 7382356485120. Its totient is φ = 3514973812064.
The previous prime is 5404044413899. The next prime is 5404044414007. The reversal of 5404044414003 is 3004144404045.
It is a cyclic number.
It is not a de Polignac number, because 5404044414003 - 216 = 5404044348467 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5404044414007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 94909251 + ... + 94966172.
It is an arithmetic number, because the mean of its divisors is an integer number (461397280320).
Almost surely, 25404044414003 is an apocalyptic number.
5404044414003 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
5404044414003 is a deficient number, since it is larger than the sum of its proper divisors (1978312071117).
5404044414003 is a wasteful number, since it uses less digits than its factorization.
5404044414003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 189875658.
The product of its (nonzero) digits is 61440, while the sum is 33.
Adding to 5404044414003 its reverse (3004144404045), we get a palindrome (8408188818048).
The spelling of 5404044414003 in words is "five trillion, four hundred four billion, forty-four million, four hundred fourteen thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.102 sec. • engine limits •