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5404044414003 = 353179189875423
BaseRepresentation
bin100111010100011101000…
…1001011100110000110011
3201010121210010222000102020
41032220322021130300303
51202014440332222003
615254330030322523
71065300154420464
oct116507211346063
921117703860366
105404044414003
1117a392a208a74
1273340b659443
133027a35a4991
141497b2b40d6b
1595889214d53
hex4ea3a25cc33

5404044414003 has 16 divisors (see below), whose sum is σ = 7382356485120. Its totient is φ = 3514973812064.

The previous prime is 5404044413899. The next prime is 5404044414007. The reversal of 5404044414003 is 3004144404045.

It is a cyclic number.

It is not a de Polignac number, because 5404044414003 - 216 = 5404044348467 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5404044414007) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 94909251 + ... + 94966172.

It is an arithmetic number, because the mean of its divisors is an integer number (461397280320).

Almost surely, 25404044414003 is an apocalyptic number.

5404044414003 is a gapful number since it is divisible by the number (53) formed by its first and last digit.

5404044414003 is a deficient number, since it is larger than the sum of its proper divisors (1978312071117).

5404044414003 is a wasteful number, since it uses less digits than its factorization.

5404044414003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 189875658.

The product of its (nonzero) digits is 61440, while the sum is 33.

Adding to 5404044414003 its reverse (3004144404045), we get a palindrome (8408188818048).

The spelling of 5404044414003 in words is "five trillion, four hundred four billion, forty-four million, four hundred fourteen thousand, three".

Divisors: 1 3 53 159 179 537 9487 28461 189875423 569626269 10063397419 30190192257 33987700717 101963102151 1801348138001 5404044414003