Base | Representation |
---|---|
bin | 11000100100110011110010… |
… | …10001011101110101010011 |
3 | 21002100022002000210221002012 |
4 | 30102121321101131311103 |
5 | 24040403102130440201 |
6 | 310534123031213135 |
7 | 14245233055343546 |
oct | 1422317121356523 |
9 | 232308060727065 |
10 | 54041313140051 |
11 | 16245879460306 |
12 | 608969a5171ab |
13 | 24200c6659ac3 |
14 | d4b88369685d |
15 | 63ab12a3a5bb |
hex | 31267945dd53 |
54041313140051 has 8 divisors (see below), whose sum is σ = 56454943343904. Its totient is φ = 51633016927360.
The previous prime is 54041313140033. The next prime is 54041313140077. The reversal of 54041313140051 is 15004131314045.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54041313140051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54041313140011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1333477076 + ... + 1333517601.
It is an arithmetic number, because the mean of its divisors is an integer number (7056867917988).
Almost surely, 254041313140051 is an apocalyptic number.
54041313140051 is a deficient number, since it is larger than the sum of its proper divisors (2413630203853).
54041313140051 is a wasteful number, since it uses less digits than its factorization.
54041313140051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2666995581.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 54041313140051 its reverse (15004131314045), we get a palindrome (69045444454096).
The spelling of 54041313140051 in words is "fifty-four trillion, forty-one billion, three hundred thirteen million, one hundred forty thousand, fifty-one".
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