Search a number
-
+
54046403153 = 131412567963
BaseRepresentation
bin110010010101011010…
…101010101001010001
312011111120211202020022
4302111122222221101
51341141334400103
640454545553225
73622214563331
oct622532525121
9164446752208
1054046403153
1120a14870696
12a584045815
13513418a612
142889cc30c1
151614c34138
hexc956aaa51

54046403153 has 4 divisors (see below), whose sum is σ = 54458971248. Its totient is φ = 53633835060.

The previous prime is 54046403143. The next prime is 54046403167. The reversal of 54046403153 is 35130464045.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54046403153 - 222 = 54042208849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54046403143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206283851 + ... + 206284112.

It is an arithmetic number, because the mean of its divisors is an integer number (13614742812).

Almost surely, 254046403153 is an apocalyptic number.

It is an amenable number.

54046403153 is a deficient number, since it is larger than the sum of its proper divisors (412568095).

54046403153 is a wasteful number, since it uses less digits than its factorization.

54046403153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 412568094.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 54046403153 its reverse (35130464045), we get a palindrome (89176867198).

The spelling of 54046403153 in words is "fifty-four billion, forty-six million, four hundred three thousand, one hundred fifty-three".

Divisors: 1 131 412567963 54046403153