Base | Representation |
---|---|
bin | 11000100101001000001010… |
… | …10001111010010000011001 |
3 | 21002101100022101012122201121 |
4 | 30102210011101322100121 |
5 | 24041043003003020210 |
6 | 310543132313045241 |
7 | 14246101123210405 |
oct | 1422440521722031 |
9 | 232340271178647 |
10 | 54052252001305 |
11 | 1624a48212a708 |
12 | 608b8319b6821 |
13 | 242114a9c907c |
14 | d4c2003b0105 |
15 | 63b05304e6da |
hex | 31290547a419 |
54052252001305 has 4 divisors (see below), whose sum is σ = 64862702401572. Its totient is φ = 43241801601040.
The previous prime is 54052252001303. The next prime is 54052252001333. The reversal of 54052252001305 is 50310025225045.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 16647150728464 + 37405101272841 = 4080092^2 + 6115971^2 .
It is not a de Polignac number, because 54052252001305 - 21 = 54052252001303 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54052252001303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5405225200126 + ... + 5405225200135.
It is an arithmetic number, because the mean of its divisors is an integer number (16215675600393).
Almost surely, 254052252001305 is an apocalyptic number.
It is an amenable number.
54052252001305 is a deficient number, since it is larger than the sum of its proper divisors (10810450400267).
54052252001305 is a wasteful number, since it uses less digits than its factorization.
54052252001305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10810450400266.
The product of its (nonzero) digits is 60000, while the sum is 34.
The spelling of 54052252001305 in words is "fifty-four trillion, fifty-two billion, two hundred fifty-two million, one thousand, three hundred five".
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