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54060032433 = 3111638182801
BaseRepresentation
bin110010010110001110…
…101010000110110001
312011112112111012002110
4302112032222012301
51341203332014213
640500154035533
73622441460001
oct622616520661
9164475435073
1054060032433
1120a2152a560
12a588718ba9
135136c50094
14288ba30001
1516160275c3
hexc963aa1b1

54060032433 has 8 divisors (see below), whose sum is σ = 78632774496. Its totient is φ = 32763656000.

The previous prime is 54060032401. The next prime is 54060032441. The reversal of 54060032433 is 33423006045.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 54060032433 - 25 = 54060032401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 54060032433.

It is not an unprimeable number, because it can be changed into a prime (54060032443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 819091368 + ... + 819091433.

It is an arithmetic number, because the mean of its divisors is an integer number (9829096812).

Almost surely, 254060032433 is an apocalyptic number.

It is an amenable number.

54060032433 is a deficient number, since it is larger than the sum of its proper divisors (24572742063).

54060032433 is a wasteful number, since it uses less digits than its factorization.

54060032433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1638182815.

The product of its (nonzero) digits is 25920, while the sum is 30.

Adding to 54060032433 its reverse (33423006045), we get a palindrome (87483038478).

The spelling of 54060032433 in words is "fifty-four billion, sixty million, thirty-two thousand, four hundred thirty-three".

Divisors: 1 3 11 33 1638182801 4914548403 18020010811 54060032433