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54061557301 = 130341490067
BaseRepresentation
bin110010010110010100…
…011110011000110101
312011112122100122211001
4302112110132120311
51341204224313201
640500250443301
73622460440453
oct622624363065
9164478318731
1054061557301
1120a22381184
12a589133531
13513736517b
14288bd099d3
151616229301
hexc9651e635

54061557301 has 4 divisors (see below), whose sum is σ = 54103048672. Its totient is φ = 54020065932.

The previous prime is 54061557289. The next prime is 54061557307. The reversal of 54061557301 is 10375516045.

54061557301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54061557301 - 25 = 54061557269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54061557307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20743731 + ... + 20746336.

It is an arithmetic number, because the mean of its divisors is an integer number (13525762168).

Almost surely, 254061557301 is an apocalyptic number.

It is an amenable number.

54061557301 is a deficient number, since it is larger than the sum of its proper divisors (41491371).

54061557301 is a wasteful number, since it uses less digits than its factorization.

54061557301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41491370.

The product of its (nonzero) digits is 63000, while the sum is 37.

The spelling of 54061557301 in words is "fifty-four billion, sixty-one million, five hundred fifty-seven thousand, three hundred one".

Divisors: 1 1303 41490067 54061557301