Base | Representation |
---|---|
bin | 11000100110100011100011… |
… | …00000101000110110001111 |
3 | 21002120000221111002020221011 |
4 | 30103101301200220312033 |
5 | 24042343441441113433 |
6 | 311021444432350051 |
7 | 14252455646112430 |
oct | 1423216140506617 |
9 | 232500844066834 |
10 | 54101312441743 |
11 | 16269268500756 |
12 | 60992440a5327 |
13 | 2425968c01198 |
14 | d50736007487 |
15 | 63c4751a13cd |
hex | 313471828d8f |
54101312441743 has 16 divisors (see below), whose sum is σ = 63910491181056. Its totient is φ = 44816265285120.
The previous prime is 54101312441731. The next prime is 54101312441963. The reversal of 54101312441743 is 34714421310145.
It is not a de Polignac number, because 54101312441743 - 213 = 54101312433551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54101312441696 and 54101312441705.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54101312441543) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 167614546 + ... + 167937007.
It is an arithmetic number, because the mean of its divisors is an integer number (3994405698816).
Almost surely, 254101312441743 is an apocalyptic number.
54101312441743 is a deficient number, since it is larger than the sum of its proper divisors (9809178739313).
54101312441743 is a wasteful number, since it uses less digits than its factorization.
54101312441743 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 335552334.
The product of its (nonzero) digits is 161280, while the sum is 40.
Adding to 54101312441743 its reverse (34714421310145), we get a palindrome (88815733751888).
The spelling of 54101312441743 in words is "fifty-four trillion, one hundred one billion, three hundred twelve million, four hundred forty-one thousand, seven hundred forty-three".
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