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54102214441 = 114918383131
BaseRepresentation
bin110010011000101111…
…100100011100101001
312011122110212020221001
4302120233210130221
51341300131330231
640504302115001
73623463143422
oct623057443451
9164573766831
1054102214441
1120a43320520
12a59a87ba61
1351428cbb52
142893490649
151619aaab61
hexc98be4729

54102214441 has 4 divisors (see below), whose sum is σ = 59020597584. Its totient is φ = 49183831300.

The previous prime is 54102214433. The next prime is 54102214499. The reversal of 54102214441 is 14441220145.

It is a happy number.

54102214441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54102214441 - 23 = 54102214433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54102214741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2459191555 + ... + 2459191576.

It is an arithmetic number, because the mean of its divisors is an integer number (14755149396).

Almost surely, 254102214441 is an apocalyptic number.

It is an amenable number.

54102214441 is a deficient number, since it is larger than the sum of its proper divisors (4918383143).

54102214441 is a wasteful number, since it uses less digits than its factorization.

54102214441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4918383142.

The product of its (nonzero) digits is 5120, while the sum is 28.

Adding to 54102214441 its reverse (14441220145), we get a palindrome (68543434586).

The spelling of 54102214441 in words is "fifty-four billion, one hundred two million, two hundred fourteen thousand, four hundred forty-one".

Divisors: 1 11 4918383131 54102214441