Base | Representation |
---|---|
bin | 11000100110100110110011… |
… | …01100011110111000001111 |
3 | 21002120012110022010120110211 |
4 | 30103103121230132320033 |
5 | 24042411031424031403 |
6 | 311022334112543251 |
7 | 14252550162243043 |
oct | 1423233154367017 |
9 | 232505408116424 |
10 | 54103060377103 |
11 | 16269a85134431 |
12 | 6099651551b27 |
13 | 2425b8709216a |
14 | d5086020a023 |
15 | 63c52887306d |
hex | 3134d9b1ee0f |
54103060377103 has 4 divisors (see below), whose sum is σ = 57285593340480. Its totient is φ = 50920527413728.
The previous prime is 54103060377077. The next prime is 54103060377161. The reversal of 54103060377103 is 30177306030145.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 54103060377103 - 213 = 54103060368911 is a prime.
It is a super-2 number, since 2×541030603771032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54103060377173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1591266481663 + ... + 1591266481696.
It is an arithmetic number, because the mean of its divisors is an integer number (14321398335120).
Almost surely, 254103060377103 is an apocalyptic number.
54103060377103 is a deficient number, since it is larger than the sum of its proper divisors (3182532963377).
54103060377103 is a wasteful number, since it uses less digits than its factorization.
54103060377103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3182532963376.
The product of its (nonzero) digits is 158760, while the sum is 40.
The spelling of 54103060377103 in words is "fifty-four trillion, one hundred three billion, sixty million, three hundred seventy-seven thousand, one hundred three".
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