Base | Representation |
---|---|
bin | 100111010111011001001… |
… | …1000110001111100000001 |
3 | 201011020002001120122110102 |
4 | 1032232302120301330001 |
5 | 1202120402301303423 |
6 | 15301252240012145 |
7 | 1065612452605040 |
oct | 116566230617401 |
9 | 21136061518412 |
10 | 5410356666113 |
11 | 17a6579321453 |
12 | 734691601055 |
13 | 30326b26b1b9 |
14 | 149c111d2557 |
15 | 95b0847bc28 |
hex | 4ebb2631f01 |
5410356666113 has 4 divisors (see below), whose sum is σ = 6183264761280. Its totient is φ = 4637448570948.
The previous prime is 5410356666103. The next prime is 5410356666119. The reversal of 5410356666113 is 3116666530145.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5410356666113 - 26 = 5410356666049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5410356666119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386454047573 + ... + 386454047586.
It is an arithmetic number, because the mean of its divisors is an integer number (1545816190320).
Almost surely, 25410356666113 is an apocalyptic number.
It is an amenable number.
5410356666113 is a deficient number, since it is larger than the sum of its proper divisors (772908095167).
5410356666113 is an equidigital number, since it uses as much as digits as its factorization.
5410356666113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 772908095166.
The product of its (nonzero) digits is 1166400, while the sum is 47.
The spelling of 5410356666113 in words is "five trillion, four hundred ten billion, three hundred fifty-six million, six hundred sixty-six thousand, one hundred thirteen".
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