Base | Representation |
---|---|
bin | 11000100110101100010101… |
… | …10010000010011010100011 |
3 | 21002120111010100122012112112 |
4 | 30103112022302002122203 |
5 | 24042433123014304421 |
6 | 311023545004145535 |
7 | 14253013616442131 |
oct | 1423261262023243 |
9 | 232514110565475 |
10 | 54106031400611 |
11 | 1627026a203363 |
12 | 609a1405382ab |
13 | 242623b76c538 |
14 | d50a62a2c751 |
15 | 63c64e5e145b |
hex | 31358ac826a3 |
54106031400611 has 4 divisors (see below), whose sum is σ = 54129627578832. Its totient is φ = 54082435222392.
The previous prime is 54106031400607. The next prime is 54106031400689. The reversal of 54106031400611 is 11600413060145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54106031400611 - 22 = 54106031400607 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54106031400011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11798085671 + ... + 11798090256.
It is an arithmetic number, because the mean of its divisors is an integer number (13532406894708).
Almost surely, 254106031400611 is an apocalyptic number.
54106031400611 is a deficient number, since it is larger than the sum of its proper divisors (23596178221).
54106031400611 is a wasteful number, since it uses less digits than its factorization.
54106031400611 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23596178220.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 54106031400611 its reverse (11600413060145), we get a palindrome (65706444460756).
The spelling of 54106031400611 in words is "fifty-four trillion, one hundred six billion, thirty-one million, four hundred thousand, six hundred eleven".
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