Base | Representation |
---|---|
bin | 11000100110110011111110… |
… | …10100011001110101100111 |
3 | 21002120212201021111101200111 |
4 | 30103121333110121311213 |
5 | 24043020023304101101 |
6 | 311025504042153451 |
7 | 14253220364414404 |
oct | 1423317724316547 |
9 | 232525637441614 |
10 | 54110134050151 |
11 | 16271a85028713 |
12 | 609aaa64b2887 |
13 | 242674372170a |
14 | d50d318632ab |
15 | 63c7de891251 |
hex | 31367f519d67 |
54110134050151 has 4 divisors (see below), whose sum is σ = 54110427846904. Its totient is φ = 54109840253400.
The previous prime is 54110134050127. The next prime is 54110134050163. The reversal of 54110134050151 is 15105043101145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54110134050151 - 29 = 54110134049639 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54110134050251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146621940 + ... + 146990521.
It is an arithmetic number, because the mean of its divisors is an integer number (13527606961726).
Almost surely, 254110134050151 is an apocalyptic number.
54110134050151 is a deficient number, since it is larger than the sum of its proper divisors (293796753).
54110134050151 is a wasteful number, since it uses less digits than its factorization.
54110134050151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 293796752.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 54110134050151 its reverse (15105043101145), we get a palindrome (69215177151296).
The spelling of 54110134050151 in words is "fifty-four trillion, one hundred ten billion, one hundred thirty-four million, fifty thousand, one hundred fifty-one".
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