Base | Representation |
---|---|
bin | 110010011001010110… |
… | …111000011110110001 |
3 | 12011200012020211122121 |
4 | 302121112320132301 |
5 | 1341310301120423 |
6 | 40505311034241 |
7 | 3623646555211 |
oct | 623126703661 |
9 | 164605224577 |
10 | 54112520113 |
11 | 20a4911a303 |
12 | a5a220b981 |
13 | 5144a99892 |
14 | 28949b4241 |
15 | 161a94445d |
hex | c995b87b1 |
54112520113 has 4 divisors (see below), whose sum is σ = 54444498928. Its totient is φ = 53780541300.
The previous prime is 54112520107. The next prime is 54112520129. The reversal of 54112520113 is 31102521145.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54112520113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54112520173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165989163 + ... + 165989488.
It is an arithmetic number, because the mean of its divisors is an integer number (13611124732).
Almost surely, 254112520113 is an apocalyptic number.
It is an amenable number.
54112520113 is a deficient number, since it is larger than the sum of its proper divisors (331978815).
54112520113 is a wasteful number, since it uses less digits than its factorization.
54112520113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 331978814.
The product of its (nonzero) digits is 1200, while the sum is 25.
The spelling of 54112520113 in words is "fifty-four billion, one hundred twelve million, five hundred twenty thousand, one hundred thirteen".
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