5411444303041 has 4 divisors (see below), whose sum is σ = 6184507774912. Its totient is φ = 4638380831172.

The previous prime is 5411444303011. The next prime is 5411444303059. The reversal of 5411444303041 is 1403034441145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5411444303041 - 2¹⁵ = 5411444270273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5411444302988 and 5411444303006.

It is not an unprimeable number, because it can be changed into a prime (5411444303011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386531735925 + ... + 386531735938.

It is an arithmetic number, because the mean of its divisors is an integer number (1546126943728).

Almost surely, 2^{5411444303041} is an apocalyptic number.

It is an amenable number.

5411444303041 is a deficient number, since it is larger than the sum of its proper divisors (773063471871).

5411444303041 is an equidigital number, since it uses as much as digits as its factorization.

5411444303041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 773063471870.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 5411444303041 its reverse (1403034441145), we get a palindrome (6814478744186).

The spelling of 5411444303041 in words is "five trillion, four hundred eleven billion, four hundred forty-four million, three hundred three thousand, forty-one".