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5411512040053 = 71077224982697
BaseRepresentation
bin100111010111111011101…
…0000001011101001110101
3201011100001120121201112211
41032233313100023221311
51202130234040240203
615302003031413421
71065653212250140
oct116576720135165
921140046551484
105411512040053
1117a7011517a49
12734954524271
133033c3739312
14149cc0827057
1595b74aeec6d
hex4ebf740ba75

5411512040053 has 8 divisors (see below), whose sum is σ = 6242385051072. Its totient is φ = 4595088994656.

The previous prime is 5411512040047. The next prime is 5411512040057. The reversal of 5411512040053 is 3500402151145.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5411512040053 - 29 = 5411512039541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5411512039997 and 5411512040024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5411512040057) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3612490600 + ... + 3612492097.

It is an arithmetic number, because the mean of its divisors is an integer number (780298131384).

Almost surely, 25411512040053 is an apocalyptic number.

It is an amenable number.

5411512040053 is a deficient number, since it is larger than the sum of its proper divisors (830873011019).

5411512040053 is a wasteful number, since it uses less digits than its factorization.

5411512040053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7224982811.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 5411512040053 its reverse (3500402151145), we get a palindrome (8911914191198).

The spelling of 5411512040053 in words is "five trillion, four hundred eleven billion, five hundred twelve million, forty thousand, fifty-three".

Divisors: 1 7 107 749 7224982697 50574878879 773073148579 5411512040053