Base | Representation |
---|---|
bin | 11000100111000111001000… |
… | …11111100101010001110011 |
3 | 21002121212021012222121220111 |
4 | 30103203210133211101303 |
5 | 24043202110340222003 |
6 | 311034324532122151 |
7 | 14254033331520010 |
oct | 1423434437452163 |
9 | 232555235877814 |
10 | 54120421414003 |
11 | 16276383a7640a |
12 | 60a0a97766357 |
13 | 24276c2b04269 |
14 | d51629c2a707 |
15 | 63cbe2ab3e6d |
hex | 3138e47e5473 |
54120421414003 has 8 divisors (see below), whose sum is σ = 63847133096960. Its totient is φ = 44892515458440.
The previous prime is 54120421413973. The next prime is 54120421414019. The reversal of 54120421414003 is 30041412402145.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54120421414003 - 221 = 54120419316851 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54120421414903) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 124701431613 + ... + 124701432046.
It is an arithmetic number, because the mean of its divisors is an integer number (7980891637120).
Almost surely, 254120421414003 is an apocalyptic number.
54120421414003 is a deficient number, since it is larger than the sum of its proper divisors (9726711682957).
54120421414003 is a wasteful number, since it uses less digits than its factorization.
54120421414003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 249402863697.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 54120421414003 its reverse (30041412402145), we get a palindrome (84161833816148).
The spelling of 54120421414003 in words is "fifty-four trillion, one hundred twenty billion, four hundred twenty-one million, four hundred fourteen thousand, three".
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