Base | Representation |
---|---|
bin | 11000100111001000010010… |
… | …10111111001001010110011 |
3 | 21002121220212100020221102101 |
4 | 30103210021113321022303 |
5 | 24043204342234432230 |
6 | 311034510154001231 |
7 | 14254054553653360 |
oct | 1423441127711263 |
9 | 232556770227371 |
10 | 54121040155315 |
11 | 16276671264971 |
12 | 60a102aa16217 |
13 | 2427791062393 |
14 | d51688091467 |
15 | 63cc2c084aca |
hex | 3139095f92b3 |
54121040155315 has 32 divisors (see below), whose sum is σ = 77452623553536. Its totient is φ = 35496928579200.
The previous prime is 54121040155267. The next prime is 54121040155433. The reversal of 54121040155315 is 51355104012145.
54121040155315 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54121040155315 - 241 = 51922016899763 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25490340 + ... + 27531790.
It is an arithmetic number, because the mean of its divisors is an integer number (2420394486048).
Almost surely, 254121040155315 is an apocalyptic number.
54121040155315 is a deficient number, since it is larger than the sum of its proper divisors (23331583398221).
54121040155315 is a wasteful number, since it uses less digits than its factorization.
54121040155315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2074419.
The product of its (nonzero) digits is 60000, while the sum is 37.
The spelling of 54121040155315 in words is "fifty-four trillion, one hundred twenty-one billion, forty million, one hundred fifty-five thousand, three hundred fifteen".
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