Base | Representation |
---|---|
bin | 11000100111001001011011… |
… | …11101100111011110111001 |
3 | 21002121222110010100201010002 |
4 | 30103210231331213132321 |
5 | 24043212121412232441 |
6 | 311035051123202345 |
7 | 14254106016524345 |
oct | 1423445575473671 |
9 | 232558403321102 |
10 | 54121654024121 |
11 | 16276956825662 |
12 | 60a11805163b5 |
13 | 242785b2a5768 |
14 | d51705808625 |
15 | 63cc65de1b9b |
hex | 31392df677b9 |
54121654024121 has 4 divisors (see below), whose sum is σ = 54121670088192. Its totient is φ = 54121637960052.
The previous prime is 54121654024007. The next prime is 54121654024129. The reversal of 54121654024121 is 12142045612145.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 54121654024121 - 222 = 54121649829817 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54121654024129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 819461 + ... + 10436226.
It is an arithmetic number, because the mean of its divisors is an integer number (13530417522048).
Almost surely, 254121654024121 is an apocalyptic number.
It is an amenable number.
54121654024121 is a deficient number, since it is larger than the sum of its proper divisors (16064071).
54121654024121 is a wasteful number, since it uses less digits than its factorization.
54121654024121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16064070.
The product of its (nonzero) digits is 76800, while the sum is 38.
Adding to 54121654024121 its reverse (12142045612145), we get a palindrome (66263699636266).
The spelling of 54121654024121 in words is "fifty-four trillion, one hundred twenty-one billion, six hundred fifty-four million, twenty-four thousand, one hundred twenty-one".
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