Base | Representation |
---|---|
bin | 11000100111001010010101… |
… | …00010001001001101111111 |
3 | 21002122000200112022120102122 |
4 | 30103211022202021031333 |
5 | 24043214112120032120 |
6 | 311035210445113155 |
7 | 14254123630032461 |
oct | 1423451242111577 |
9 | 232560615276378 |
10 | 54122133361535 |
11 | 16277082359988 |
12 | 60a1294b587bb |
13 | 24279066a4975 |
14 | d5174d342131 |
15 | 63cc93027a25 |
hex | 31394a88937f |
54122133361535 has 4 divisors (see below), whose sum is σ = 64946560033848. Its totient is φ = 43297706689224.
The previous prime is 54122133361529. The next prime is 54122133361573. The reversal of 54122133361535 is 53516333122145.
54122133361535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54122133361535 - 24 = 54122133361519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5412213336149 + ... + 5412213336158.
It is an arithmetic number, because the mean of its divisors is an integer number (16236640008462).
Almost surely, 254122133361535 is an apocalyptic number.
54122133361535 is a deficient number, since it is larger than the sum of its proper divisors (10824426672313).
54122133361535 is a wasteful number, since it uses less digits than its factorization.
54122133361535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10824426672312.
The product of its digits is 972000, while the sum is 44.
The spelling of 54122133361535 in words is "fifty-four trillion, one hundred twenty-two billion, one hundred thirty-three million, three hundred sixty-one thousand, five hundred thirty-five".
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