Base | Representation |
---|---|
bin | 111101100001111111010100… |
… | …1110010101111000111011111 |
3 | 2121222100101100222101222120011 |
4 | 1323003332221302233013133 |
5 | 1031420030444012031020 |
6 | 5155035024442504051 |
7 | 222000543032112550 |
oct | 17303765162570737 |
9 | 2558311328358504 |
10 | 541233152455135 |
11 | 1474a9766707188 |
12 | 5085273b805027 |
13 | 1a3000b4a70cba |
14 | 9791b78038327 |
15 | 4288ab2a8a35a |
hex | 1ec3fa9caf1df |
541233152455135 has 16 divisors (see below), whose sum is σ = 742269666442752. Its totient is φ = 371127775860000.
The previous prime is 541233152455133. The next prime is 541233152455157. The reversal of 541233152455135 is 531554251332145.
It is not a de Polignac number, because 541233152455135 - 21 = 541233152455133 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (541233152455133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69777771 + ... + 77145340.
It is an arithmetic number, because the mean of its divisors is an integer number (46391854152672).
Almost surely, 2541233152455135 is an apocalyptic number.
541233152455135 is a deficient number, since it is larger than the sum of its proper divisors (201036513987617).
541233152455135 is a wasteful number, since it uses less digits than its factorization.
541233152455135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147028374.
The product of its digits is 5400000, while the sum is 49.
The spelling of 541233152455135 in words is "five hundred forty-one trillion, two hundred thirty-three billion, one hundred fifty-two million, four hundred fifty-five thousand, one hundred thirty-five".
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