Base | Representation |
---|---|
bin | 100111011000011001000… |
… | …1110110011011011101101 |
3 | 201011102121112112020200021 |
4 | 1032300302032303123231 |
5 | 1202134300343100240 |
6 | 15302245140002141 |
7 | 1066016555644345 |
oct | 116606216633355 |
9 | 21142545466607 |
10 | 5412501534445 |
11 | 17a747a015805 |
12 | 734b8b990351 |
13 | 303520738765 |
14 | 149d75ddbd25 |
15 | 95bd190854a |
hex | 4ec323b36ed |
5412501534445 has 4 divisors (see below), whose sum is σ = 6495001841340. Its totient is φ = 4330001227552.
The previous prime is 5412501534439. The next prime is 5412501534511. The reversal of 5412501534445 is 5444351052145.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2704176335844 + 2708325198601 = 1644438^2 + 1645699^2 .
It is a cyclic number.
It is not a de Polignac number, because 5412501534445 - 27 = 5412501534317 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541250153440 + ... + 541250153449.
It is an arithmetic number, because the mean of its divisors is an integer number (1623750460335).
Almost surely, 25412501534445 is an apocalyptic number.
It is an amenable number.
5412501534445 is a deficient number, since it is larger than the sum of its proper divisors (1082500306895).
5412501534445 is a wasteful number, since it uses less digits than its factorization.
5412501534445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1082500306894.
The product of its (nonzero) digits is 960000, while the sum is 43.
The spelling of 5412501534445 in words is "five trillion, four hundred twelve billion, five hundred one million, five hundred thirty-four thousand, four hundred forty-five".
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