Base | Representation |
---|---|
bin | 11000100111001111111001… |
… | …01011011110011011010001 |
3 | 21002122022101211020212101011 |
4 | 30103213330223132123101 |
5 | 24043241222232332040 |
6 | 311040423213210521 |
7 | 14254260661240642 |
oct | 1423477453363321 |
9 | 232568354225334 |
10 | 54125122152145 |
11 | 16278376463570 |
12 | 60a1989a90a41 |
13 | 2427c91963015 |
14 | d5195426b6c9 |
15 | 63cdba6053ea |
hex | 3139fcade6d1 |
54125122152145 has 32 divisors (see below), whose sum is σ = 71258359536000. Its totient is φ = 39139547328000.
The previous prime is 54125122152071. The next prime is 54125122152293.
54125122152145 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-54125122152145 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54125122152098 and 54125122152107.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 58083106 + ... + 59007604.
It is an arithmetic number, because the mean of its divisors is an integer number (2226823735500).
Almost surely, 254125122152145 is an apocalyptic number.
54125122152145 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54125122152145 is a deficient number, since it is larger than the sum of its proper divisors (17133237383855).
54125122152145 is a wasteful number, since it uses less digits than its factorization.
54125122152145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 930577.
The product of its digits is 160000, while the sum is 40.
It can be divided in two parts, 5412512 and 2152145, that added together give a palindrome (7564657).
The spelling of 54125122152145 in words is "fifty-four trillion, one hundred twenty-five billion, one hundred twenty-two million, one hundred fifty-two thousand, one hundred forty-five".
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