Base | Representation |
---|---|
bin | 111101100010100100000101… |
… | …1100000010110001111011001 |
3 | 2121222121221011001102102122121 |
4 | 1323011020023200112033121 |
5 | 1031422324140402310040 |
6 | 5155135202444421241 |
7 | 222006336330353653 |
oct | 17305101340261731 |
9 | 2558557131372577 |
10 | 541312101213145 |
11 | 14752a19a180629 |
12 | 50865ab3547821 |
13 | 1a307687167122 |
14 | 97959073276d3 |
15 | 428ab83b04c4a |
hex | 1ec520b8163d9 |
541312101213145 has 16 divisors (see below), whose sum is σ = 670529479196160. Its totient is φ = 419079748348800.
The previous prime is 541312101213137. The next prime is 541312101213157.
541312101213145 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 541312101213145 - 23 = 541312101213137 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 541312101213145.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 132131986 + ... + 136167124.
It is an arithmetic number, because the mean of its divisors is an integer number (41908092449760).
Almost surely, 2541312101213145 is an apocalyptic number.
It is an amenable number.
541312101213145 is a deficient number, since it is larger than the sum of its proper divisors (129217377983015).
541312101213145 is a wasteful number, since it uses less digits than its factorization.
541312101213145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4900656.
The product of its (nonzero) digits is 14400, while the sum is 34.
It can be divided in two parts, 54131210 and 1213145, that added together give a palindrome (55344355).
The spelling of 541312101213145 in words is "five hundred forty-one trillion, three hundred twelve billion, one hundred one million, two hundred thirteen thousand, one hundred forty-five".
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