Base | Representation |
---|---|
bin | 11000100111011100101110… |
… | …10010100101011101011111 |
3 | 21002122222011220221210200122 |
4 | 30103232113102211131133 |
5 | 24043344324313010020 |
6 | 311043522542345155 |
7 | 14254623461101355 |
oct | 1423562722453537 |
9 | 232588156853618 |
10 | 54132011063135 |
11 | 16280291032335 |
12 | 60a3190b8b1bb |
13 | 242881bc42005 |
14 | d5200914b7d5 |
15 | 63d1702c9125 |
hex | 313b974a575f |
54132011063135 has 4 divisors (see below), whose sum is σ = 64958413275768. Its totient is φ = 43305608850504.
The previous prime is 54132011063129. The next prime is 54132011063161. The reversal of 54132011063135 is 53136011023145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54132011063135 - 28 = 54132011062879 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54132011063095 and 54132011063104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5413201106309 + ... + 5413201106318.
It is an arithmetic number, because the mean of its divisors is an integer number (16239603318942).
Almost surely, 254132011063135 is an apocalyptic number.
54132011063135 is a deficient number, since it is larger than the sum of its proper divisors (10826402212633).
54132011063135 is a wasteful number, since it uses less digits than its factorization.
54132011063135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10826402212632.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 54132011063135 in words is "fifty-four trillion, one hundred thirty-two billion, eleven million, sixty-three thousand, one hundred thirty-five".
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