Base | Representation |
---|---|
bin | 1010000101010101… |
… | …00101010010111111 |
3 | 111222021022112220212 |
4 | 11002222211102333 |
5 | 42041314120432 |
6 | 2253100303035 |
7 | 251102236106 |
oct | 50252452277 |
9 | 14867275825 |
10 | 5413426367 |
11 | 2328813398 |
12 | 1070b41a7b |
13 | 6836c148b |
14 | 394d5d03d |
15 | 21a3bd2b2 |
hex | 142aa54bf |
5413426367 has 4 divisors (see below), whose sum is σ = 5588053056. Its totient is φ = 5238799680.
The previous prime is 5413426327. The next prime is 5413426379. The reversal of 5413426367 is 7636243145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5413426367 - 210 = 5413425343 is a prime.
It is a super-3 number, since 3×54134263673 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5413426327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87313298 + ... + 87313359.
It is an arithmetic number, because the mean of its divisors is an integer number (1397013264).
Almost surely, 25413426367 is an apocalyptic number.
5413426367 is a deficient number, since it is larger than the sum of its proper divisors (174626689).
5413426367 is a wasteful number, since it uses less digits than its factorization.
5413426367 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 174626688.
The product of its digits is 362880, while the sum is 41.
The square root of 5413426367 is about 73575.9904248662. The cubic root of 5413426367 is about 1755.8634741425.
The spelling of 5413426367 in words is "five billion, four hundred thirteen million, four hundred twenty-six thousand, three hundred sixty-seven".
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