Base | Representation |
---|---|
bin | 100111011001010000001… |
… | …1111101011010101101111 |
3 | 201011121101110110202210212 |
4 | 1032302200133223111233 |
5 | 1202202042432422003 |
6 | 15303152502053035 |
7 | 1066113450662501 |
oct | 116624037532557 |
9 | 21147343422725 |
10 | 5414351451503 |
11 | 17a8239273885 |
12 | 73540741a17b |
13 | 303756a85237 |
14 | 14a0ad989d71 |
15 | 95c8e021dd8 |
hex | 4eca07eb56f |
5414351451503 has 4 divisors (see below), whose sum is σ = 5414632167120. Its totient is φ = 5414070735888.
The previous prime is 5414351451449. The next prime is 5414351451533. The reversal of 5414351451503 is 3051541534145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5414351451503 - 232 = 5410056484207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5414351451533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140328875 + ... + 140367452.
It is an arithmetic number, because the mean of its divisors is an integer number (1353658041780).
Almost surely, 25414351451503 is an apocalyptic number.
5414351451503 is a deficient number, since it is larger than the sum of its proper divisors (280715617).
5414351451503 is a wasteful number, since it uses less digits than its factorization.
5414351451503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 280715616.
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 5414351451503 its reverse (3051541534145), we get a palindrome (8465892985648).
The spelling of 5414351451503 in words is "five trillion, four hundred fourteen billion, three hundred fifty-one million, four hundred fifty-one thousand, five hundred three".
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